(2x^2-3x+5)(x-4)=0

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Solution for (2x^2-3x+5)(x-4)=0 equation: 


Simplifying
(2x2 + -3x + 5)(x + -4) = 0

Reorder the terms:
(5 + -3x + 2x2)(x + -4) = 0

Reorder the terms:
(5 + -3x + 2x2)(-4 + x) = 0

Multiply (5 + -3x + 2x2) * (-4 + x)
(5(-4 + x) + -3x * (-4 + x) + 2x2 * (-4 + x)) = 0
((-4 * 5 + x * 5) + -3x * (-4 + x) + 2x2 * (-4 + x)) = 0
((-20 + 5x) + -3x * (-4 + x) + 2x2 * (-4 + x)) = 0
(-20 + 5x + (-4 * -3x + x * -3x) + 2x2 * (-4 + x)) = 0
(-20 + 5x + (12x + -3x2) + 2x2 * (-4 + x)) = 0
(-20 + 5x + 12x + -3x2 + (-4 * 2x2 + x * 2x2)) = 0
(-20 + 5x + 12x + -3x2 + (-8x2 + 2x3)) = 0

Combine like terms: 5x + 12x = 17x
(-20 + 17x + -3x2 + -8x2 + 2x3) = 0

Combine like terms: -3x2 + -8x2 = -11x2
(-20 + 17x + -11x2 + 2x3) = 0

Solving
-20 + 17x + -11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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